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The volume of the similar object is 3240 cubic centimetres.Find its height.

2007-01-01 18:55:45 · 7 answers · asked by Anurag 2 in Science & Mathematics Mathematics

7 answers

h = 5
v = 120
a = ?

hx = New height
ax^2 = New area of base
vx^3 = New volume = 3240

120x^3 = 3240
x^3 = 27
x = 3

New height is 5 * 3 = 15

2007-01-01 20:40:19 · answer #1 · answered by Tom :: Athier than Thou 6 · 0 0

The dimensions increase as the cube root of the volume.

Let h = height of larger object.

Then

h/5 = (3240/120)^(1/3) = 27^(1/3) = 3
h = 15 cm

2007-01-02 03:59:19 · answer #2 · answered by Northstar 7 · 1 0

Let h be the height.

By 3-D similarity,

(h/5)^3 = (3240/120)

Solve for h, h = 15 cm

2007-01-02 03:35:35 · answer #3 · answered by sahsjing 7 · 0 0

It has to be 135 cm.

As the height of first object is 5 cm, the cross-sectional area is 120 cm^3/5cm = 24 cm^2

Similar object has cross-sectional area of 24 cm^2.

Therefore height = 3240 cm^3 / 24 cm^2 = 135 cm

2007-01-02 04:07:34 · answer #4 · answered by chem_wiz 2 · 0 1

i suppose you can use ratio and proportion since the two objects are similar... 5/120 * h/3240.. manipulating, u'll have an h that's 135 cm--- and that's the height...

2007-01-02 03:07:50 · answer #5 · answered by shang 1 · 0 2

if area is assumed constant, then h=135.

if the body is only similar to the first body, then h=15.

2007-01-02 04:13:08 · answer #6 · answered by sweet tooth 2 · 0 0

H1=5cm,V1=120cubic centimeters,V2=3240,H2=?
V1=L*B*H1, V2=L*B*H2, V1/V2=H1/H2, H2=(H1*V2)/V1
H2=135cm


ANSWER = 135CM

2007-01-02 04:04:30 · answer #7 · answered by nitesh m 1 · 0 0

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