h = 5
v = 120
a = ?
hx = New height
ax^2 = New area of base
vx^3 = New volume = 3240
120x^3 = 3240
x^3 = 27
x = 3
New height is 5 * 3 = 15
2007-01-01 20:40:19
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answer #1
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answered by Tom :: Athier than Thou 6
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The dimensions increase as the cube root of the volume.
Let h = height of larger object.
Then
h/5 = (3240/120)^(1/3) = 27^(1/3) = 3
h = 15 cm
2007-01-02 03:59:19
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answer #2
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answered by Northstar 7
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Let h be the height.
By 3-D similarity,
(h/5)^3 = (3240/120)
Solve for h, h = 15 cm
2007-01-02 03:35:35
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answer #3
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answered by sahsjing 7
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It has to be 135 cm.
As the height of first object is 5 cm, the cross-sectional area is 120 cm^3/5cm = 24 cm^2
Similar object has cross-sectional area of 24 cm^2.
Therefore height = 3240 cm^3 / 24 cm^2 = 135 cm
2007-01-02 04:07:34
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answer #4
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answered by chem_wiz 2
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i suppose you can use ratio and proportion since the two objects are similar... 5/120 * h/3240.. manipulating, u'll have an h that's 135 cm--- and that's the height...
2007-01-02 03:07:50
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answer #5
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answered by shang 1
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if area is assumed constant, then h=135.
if the body is only similar to the first body, then h=15.
2007-01-02 04:13:08
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answer #6
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answered by sweet tooth 2
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H1=5cm,V1=120cubic centimeters,V2=3240,H2=?
V1=L*B*H1, V2=L*B*H2, V1/V2=H1/H2, H2=(H1*V2)/V1
H2=135cm
ANSWER = 135CM
2007-01-02 04:04:30
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answer #7
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answered by nitesh m 1
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