simplifying?

Question

(2ab^2)^3
_________
-14(a^2b)^2

Answer 1

[(2ab^2)^3] / [-14 (a^2b)^2]

Your first step is to apply those outside exponents to every term in the brackets. Use the property that (ab)^m = a^m b^m.
This means in the numerator, we're going to take everything in the brackets to the power of 3, and in the denominator, to the power of 2.

[(2^3)(a^3)(b^2)^3] / [-14 (a^2)^2(b^2)]

Simplifying the numbers first, we get

[8 a^3 (b^2)^3] / [-14 (a^2)^2 (b^2) ]

Remember that whenever we have a power to a power (or an exponent to an exponent), we multiply the exponents. that is, (a^m)^n = a^(mn).

[8 a^3 b^6] / [-14 (a^4) (b^2)]

Now, we can cancel out terms. Since there is a^3 in the numerator and a^4 in the denominator, we are left with just a^1 in the denominator. Same with the b terms.

[8 b^4] / [-14 (a^1)]. a^1 is just a, so we get
[8 b^4] / [-14a]

Let's bump the negative sign to the top.

[-8 b^4] / [14a]

And now, compare the numeric values; they are both even numbers and thus can be reduced, the same way we reduce
-8/14 as -4/7

[-4 b^4] / [7a]

Or, to make the answer absolutely clean,

(-4/7) [(b^4)/a]

Answer 2

Maybe you find sumthing here to help you.
Good Luck