What are the exact values of x for cos(x-(pi/2))=-(Squareroot of 3)/2???

Question

the answer is found in the domain 0

Answer 1

The angle whose cosine is -√3 / 2 is 5π/6. Therefore x-π/2 = 5π/6

x = 5π/6 + π/2 = (5+3)π/6 = 8π/6 = 4π/3. Since cos x = cos x + 2nπ, you can add multiples of 2π to this answer:

4π/3 + 2nπ, n = 0,1,2,....

But in the domain 0

Answer 2

i'm wondering if you can use a graphing calc. for this, if yes, this is so somple graph in radian mode, then check the zeros (x-intercepts) or you can use degres and convert to radian.