need help with algebra word problem?

Question

Of all pairs of consecutive odd integers whose sum is greater than 75, find the pair whose sum is the least.

Answer 1

Okay, so what do we know? Consecutive odd-number integers... so let's start there. x + y > 75. But we also know that y has to be 2 integers higher than x, by defining 'consecutive', so y = x +2. The problem says the sum is GREATER THAN 75, I'll assume that doesn't mean ALSO EQUAL TO, so the formula can be re-written as: x + (x+2) > 75, but we want to stay as close to 75 as possible (the least or lowest sum). x + x + 2 > 75, 2x + 2 > 75, 2x > 73 gives us 36.5, but integers refer to whole number units, if we plug in 36.5 for x in our problem, we get EXACTLY EQUALS 73, not > 73. Besides 36.5 isn't odd OR an integer, try the next highest 37. 37 x 2 is > 73. Therefore if x = 37, then y = x +2, so y = 39. 37 + 39 = 76...

Answer 2

Well, this is asking a question that first makes sure you understand what consecutive odd integers is.

1, 3, 5, 7 are all consecutive odd integers.

Now we have to find those whose sum is greater than 75. So take 76 and divide it by two since we are dealing with 2 numbers. 76 / 2 = 38 (this is the midpoint between 0 and 76), but this is an even integer so we should go one less and one more than this as a start.

If you take one away from 38 you get 37, and when you add one you get 39. So two consecutive odd integers whose sum is greater than 75 is 37 and 39.

And since this is the least number greater than 75 who has two consecutive odd integers than this must be the correct answer.

Answer 3

37+39 i think

Answer 4

Your supposed to anwer that urself...asking questions online isnt good and is that homework?