A pulley system lifts a 1,345 N weight a distance of .975 m. Bart the physics guy's helper Larry pulls the rope a distance of 3.9 m exerting a force of 375 N.
What is the Ideal mechanical advantage?!
2007-01-01 13:16:08 · 3 answers · asked by pmwschoolstore 1 in Science & Mathematics ➔ Physics
The ideal mechanical advantage is the ratio of the distances. In this case, that's 3.9 / .975 = 4. However, the actual mechanical advantage is the effective force divided by the exerted force, and that's 1345 / 375 = 3.59. The difference is due to friction lost in the pulley. Note that the work exerted is (375 N)*(3.9 m) = 1463 J, while the work done on the weight is only (1345 N)*(.975 m) = 1311 J. 152 J are lost to friction as heat, and this results in the difference in mechanical advantage.
2007-01-01 13:18:43 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Work = Force x displacement.
Work done by the force of 1345 N is
1345 x 0.975 J.
The distance moved by the other force is 3.9m.
If the system were ideal one,
the other force needed be F.
(In an ideal machine work will be the same)
F x 3.9 =1345 x 0.975
F = 336.25 N.
The mechanical advantage (ideal) is the load / effort.
1345 / 336.25 = 4.
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Note that the distance moved by the effort will be the same for ideal and real pulley. The effort will change.
2007-01-01 22:21:50 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
to lodge that it creates. 5.34 little 2 kl of momentum.
2007-01-01 21:18:22 · answer #3 · answered by Anonymous · 0⤊ 1⤋