I do not understand this stuff at all...!!!
a retental car agency charges $15 per day plus $.15 per mile to rent a certain car.Another agency charges $19 per day plus $.08 per mile to rent the same car.How many many miles per day will have to be driven for the cost of a car from the first agency to equal the cost of a car from the second agency?
can someone help...?please n thank you
2007-01-01 13:08:10 · 12 answers · asked by Hot_Chick 2 in Science & Mathematics ➔ Mathematics
This is just setting two equations equal to each other
Let "m" equal miles
the first equation is
15 + 0.15(m) = cost of 1st
the second is
19 + 0.08(m) = cost of 2nd
set them equal to each other and solve for x
15 + 0.15t = 19 + 0.08t
0.07t = 4
m = 57.14 miles
2007-01-01 13:12:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Okay, lets take x as the variable here. x = # of miles, as that is the only thing in this problem that is unknown. (Technically, there are 2, the other one being # of days, but since the question says per day, we can make this variable 1). Make two equations for the car agencies showing the total cost of renting a car that drives x miles in 1 day.
#1: .15x + 15
#2: .08x + 19
Since you are looking for when the cost is equal, set the 2 equations equal to each other.
.15x + 15 = .08x + 19
.15x - .08x = 19 - 15
.07x = 4
x = 57.14
Hope that helps!
2007-01-01 21:15:52 · answer #2 · answered by teekshi33 4 · 0⤊ 0⤋
Just make an equation by letting x be the distance driven. Then the cost for the first agency is $15 + .15x and the cost for the second agency is $19 + .08x To find the distance at which both agencies cost the same, just set those two equations equal to each other and solve for x.
15 + .15x = 19 + .08x
x will be the distance at which they are equal.
2007-01-01 21:11:14 · answer #3 · answered by rscanner 6 · 0⤊ 0⤋
Make a system of equations and set them equal to each other, then solve for the variable.
The equation for the first car agency is 15 + .15m
The equation for the second car agency is 19 + .08m
15 + .15m = 19 + .08m
Now solve for m
15 + .15m - .15m = 19 + .08m - .15m
15 = 19 - .07m
15 - 19 = 19 - 19 - .07m
-4 = -.07m
-4 / -.07 = -.07 / -.07m
m = 57.14 miles
2007-01-01 21:19:01 · answer #4 · answered by j 4 · 0⤊ 0⤋
n = number of miles driven each day
Cost at first agency per day = 15 + 0.15n
Cost at second agency per day = 19 + 0.08n
Since you want the cost to be equal, you make the two formulae equal, so:
15 + 0.15n = 19 + 0.08n
Subtract 15 from both sides and you get:
0.15n = 4 + 0.08n
Subtract 0.08n from both sides and you get:
0.07n = 4
Divide both sides by 0.07 and you get:
n = 4/0.07 = 57.1 miles
2007-01-01 21:19:38 · answer #5 · answered by Nicole B 5 · 0⤊ 0⤋
Cost1=15+.15m
Cost2=19+.08m
Cost1=Cost2
15+.15m=19+.08m
.15m-.08m=19-15
.07m=4
m=57
2007-01-01 21:14:11 · answer #6 · answered by Professor Maddie 4 · 0⤊ 0⤋
agency A
c=15+.15m
agency B
c=19+.08m
they are equal when
15+.15m=19+.08m subtract 15 from each side
.15m=4+.08m subtract .08m from each side
.07m=4 divide by .07
m=4/.07=57.14 miles
agency A is cheaper if you drive <=57 miles
agency B is cheaper if you drive >=58 miles
2007-01-01 22:54:15 · answer #7 · answered by yupchagee 7 · 0⤊ 0⤋
let x be the miles
15 + 0.15x = 19 + 0.08x
0.07x = 4
x = 54 1/7 miles is the break even point.
2007-01-01 21:11:15 · answer #8 · answered by feanor 7 · 0⤊ 0⤋
15+(.15xA)=19+(.08xB) Its impossible because you get .15xA=4+(.08xB) you need to know either A or B
2007-01-01 21:15:22 · answer #9 · answered by Anonymous · 0⤊ 0⤋
y = $.15x + $15
y = %.08 + $19
But I used the formula for slope, so I don't think this answer is right.
2007-01-01 21:12:58 · answer #10 · answered by Ironica 2 · 0⤊ 0⤋