i cant write out the problem here, so i did it on paint and here't the link:
http://i16.tinypic.com/3yrudk7.jpg
is the answer x to the 9th power?
2007-01-01 12:51:51 · 13 answers · asked by kitty 3 in Science & Mathematics ➔ Mathematics
The answer is x^6 In the case of your problem multiply the exponents. You would see this to be the case if you just expanded the problem of (x^3)^2 to (x^3)(x^3). Now you since you add exponents when the terms are multiplied that would give 3 + 3 = 6.
2007-01-01 12:55:59 · answer #1 · answered by rscanner 6 · 0⤊ 0⤋
No, remember that squaring something is multiplying it by itself.
so it would be x^3 times x^3.
To multiply things with the same base, you keep the base and add the powers. 3 + 3 = 6, so the answer would be x to the 6th power.
For future reference, this is also a rule, the power of a power rule, you just multiply the powers. 2 * 3 = 6.
2007-01-01 13:09:01 · answer #2 · answered by teekshi33 4 · 0⤊ 0⤋
(x^3)^2
Rule of thumb: Whenever you have a power to a power (i.e. an exponent to an exponent), you merely multiply the exponents. For instance,
(2^2)^3 = 2^6, and
(3^1)^4 = 3^4.
In your case, it's no different.
(x^3)^2 = x^6
Good question though on asking if it's x^9; now you know it's not.
Other rules of thumb:
Same base, multiplying: Whenever you're multiplying two bases to powers (i.e. 2^3 x 2^2), you keep the base and ADD the powers. Therefore, 2^3 x 2^2 = 2^(3 + 2) = 2^5
Same base, dividing. Whenver you're dividing two bases to powers (i.e. (2^3)/(2^2)), you keep the base and SUBTRACT the powers. In our case, (2^3)/(2^2) = 2^(3 - 2) = 2^1.
2007-01-01 12:56:33 · answer #3 · answered by Puggy 7 · 0⤊ 0⤋
Whenever you have a power to a power, you multiply. So (x^3) ^ 2 = x^(2 * 3) = x ^ 6
2007-01-01 13:10:29 · answer #4 · answered by j 4 · 0⤊ 0⤋
It will be x^6. You just have to multiply 3 and 2.
2007-01-01 12:59:58 · answer #5 · answered by lois lane 3 · 0⤊ 0⤋
The rule here is that you multiply the indices. So it's x to the sixth power, which we write here in Yahoo as
x^6.
You could have written your problem as (x^3)^2
2007-01-01 12:54:51 · answer #6 · answered by Hy 7 · 0⤊ 0⤋
(x^3)^2 when you raise to a term to a power, multiply exponents
x^(3*2)=x^6
2007-01-01 14:58:16 · answer #7 · answered by yupchagee 7 · 0⤊ 0⤋
when you raise an exponent to another exponent, you multiply the exponents. so, (x^3)^2 would be equal to x^6, which is x to the 6th power
2007-01-01 12:53:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋
(x^3)^2=x^6
There is a rule where you are able to simply multiply the exponents in equations such as this but I can't remember the name of the rule, but basically:
x^3 = xxx so
(xxx)^2 = xxx times xxx or x^6
2007-01-01 13:00:01 · answer #9 · answered by JT 1 · 0⤊ 0⤋
its x to the 6th power--you do 3*2.
2007-01-01 12:55:41 · answer #10 · answered by Anonymous · 0⤊ 0⤋