find the equation for the line passing through points....?

Question

(2, -3) and (-2,5) ... show all steps..please and thank you!

Answer 1

The equation of a line is usually in the form y = mx + b, where m is the slope of a line and b is the y-intercept. To find the slope, you do change in y-values / change is x-values.

1. Find the slope.

(5 - -3) / (-2 - 2)
8 / -4
-2.

2. Plug the answer in as m.

y = -2x + b.

3. Use one of the points given for your x and y values.

-3 = -2(2) + b.

4. Solve for b.

-3 = -4 + b.
-3 + 4 = b
1 = b

5. Plug in m and b in the final equation.

y = -2x + 1

Hope that helps!

Answer 2

equation of line passing through A(2,-3) and B(-2,5) points.
slope,m= (y2-y1)/x2-x1
let the point of A be the x1 and y1 values,and B be the x2 and y2 values.
m=5-(-3)/-2-2=8/-4
m=-2
equation of the line
y-y1=m(x-x1)
y-(-3)=-2(x-2)
y+3=-2x+4
y=-2x+4-3
y=-2x+1
equation of the line passing through points (2,-3) and (-2,5) is
-2x-y+1=0 or y=-2x+1

Answer 3

you first find the slope between those points.. namely..

m=-2..

then, by using the point slope formula..

and using one of the points given.. I'll use, (2,-3)..
you get
y+3=-2(x-2)..

y=-2x +1 or in standard form..

2x + y =1..

Answer 4

Slope:
(y2-y1)/(x2-x1)
(5+3)/(-2-2)
8/-4=-2

Point-Slope form:
(y-y1)=m(x-x1)
y+3=-2(x-2)
y+3=-2x+4
y=-2x+1

Check:
-3=-2(2)+1
-3=-4+1
-3=-3

5=-2(-2)+1
5=4+1
5=5