Factor completely:
3x2 – 30x + 48
2007-01-01 10:49:13 · 6 answers · asked by Just Wondering 5 in Science & Mathematics ➔ Mathematics
Your first step would be to notice that 3 is divisible by all of the numbers. Therefore, factor 3 out of the polynomial.
3(x^2 - 10x + 16)
Now, factor the inside normally. Note that -8 + -2 = -10 (the middle coefficient), and (-8)(-2) = 16. So our factors would be
(x - 8) (x - 2)
3(x - 8) (x - 2)
2007-01-01 10:54:25 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋
First take a 3 out so you have 3(x^2-10x+16) then (x-8)(x-2) so it all =s 3(x-8)(x-2). Good luck
2007-01-01 11:03:00 · answer #2 · answered by Dirk D 2 · 0⤊ 0⤋
First, you can take 3 out of each..
So, 3(x^2 - 10x + 16)
3 (x-8)(x-2)
x=8, 2
2007-01-01 10:54:11 · answer #3 · answered by Scott Z 1 · 1⤊ 0⤋
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2016-05-23 04:11:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
-30x+54 ?
2007-01-01 10:54:36 · answer #5 · answered by jimdepo 1 · 0⤊ 0⤋
take 3 out of each
the answer is x=8,2
2007-01-01 10:58:52 · answer #6 · answered by @(cool-girl)@ . 2 · 0⤊ 0⤋