Factor using the difference of squares method: (x^2 +8)?

Question

Please show details I don't understand, thank you

Answer 1

x² + 8 = x² - (-8)
= x² - (√(-8))²
Now √(-8) = √(8) * √(-1) = 2√2 * i where i = √(-1)

So x² + 8 = x² - (√(-8))²

= (x + 2√2 * i )(x - 2√2 * i )

Answer 2

a ideal trinomial sq. is a trinomial (a polynomial with 3 words) that is written because the sq. of a binomial. as an celebration: x^2 + 4x + 4 = (x+2)^2 x^2 - 6x + 9 = (x-3)^2

Answer 3

x^2 + 8 = x^2 - (-8)

If this is a difference of two squares, find the square roots of x^2 and -8. The square roots are x and 2i*sqrt(2), where i is the square root of -1; this is because sqrt(8) = sqrt(4*2) = sqrt(4)*sqrt(2) = 2*sqrt(2).

So therefore

x^2 - (-8) = (x+2i*sqrt(2))(x-2i*sqrt(2))

Answer 4

Difference of two squares

The word difference means the difference of a positive ( +) and a negative ( - ) number

a² - b²

(a + b)( a - b) = a² + b - b - b² = a² - b²

Click on the URL below for additional information concerning the difference of two squares.

regentsprep.org/Regents/math/factor/Lfactps.htm

- - - - - - - - -s-