Finding all the prime numbers that, when multiplied, will give a number
so let's take 84:
2*42
2*2*21
2*2*3*7
all of these numbers are prime, so this is the prime factorization form
2^2 * 3 * 7
2007-01-01 06:45:23
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answer #1
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answered by Anonymous
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first of all, someone wrote that 2^5=36. that is entirely incorrect, because 2^5 = 32.
The prime factorization of 36 is as follows:
36 = 3*3*2*2 or 3^2 * 2^2
As explained previously, the prime factorization of #s breaks them down into multiplication of prime factors that cannot be broken down.
so 50 = 5^2 * 2
2007-01-01 07:29:20
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answer #2
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answered by David 3
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It is breaking down a composite number to prime factors. You only divide by prime numbers. So, 36 would be factored:
32/2=16
16/2=8
8/2=4
4/2=2
2/2=1
The numbers you divided by should be prime numbers. So, the prime factorization is 2*2*2*2*2=32 or 2^5=32.
2007-01-01 06:46:38
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answer #3
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answered by TheSeventhX 2
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It is breaking a number into its smallest numbers that when multiplied equal the number. Example 210
It breaks down to 2x3x5x7
the 2,3,5 and 7 are not made up of smaller numbers (one doesn't count).
2007-01-01 06:46:18
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answer #4
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answered by ignoramus 7
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I'd expect more people would answer if you asked rather than demanded.
2007-01-01 06:44:29
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answer #5
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answered by All hat 7
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