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Finding all the prime numbers that, when multiplied, will give a number

so let's take 84:
2*42
2*2*21
2*2*3*7
all of these numbers are prime, so this is the prime factorization form
2^2 * 3 * 7

2007-01-01 06:45:23 · answer #1 · answered by Anonymous · 0 0

first of all, someone wrote that 2^5=36. that is entirely incorrect, because 2^5 = 32.

The prime factorization of 36 is as follows:
36 = 3*3*2*2 or 3^2 * 2^2

As explained previously, the prime factorization of #s breaks them down into multiplication of prime factors that cannot be broken down.

so 50 = 5^2 * 2

2007-01-01 07:29:20 · answer #2 · answered by David 3 · 0 0

It is breaking down a composite number to prime factors. You only divide by prime numbers. So, 36 would be factored:
32/2=16
16/2=8
8/2=4
4/2=2
2/2=1
The numbers you divided by should be prime numbers. So, the prime factorization is 2*2*2*2*2=32 or 2^5=32.

2007-01-01 06:46:38 · answer #3 · answered by TheSeventhX 2 · 0 1

It is breaking a number into its smallest numbers that when multiplied equal the number. Example 210
It breaks down to 2x3x5x7
the 2,3,5 and 7 are not made up of smaller numbers (one doesn't count).

2007-01-01 06:46:18 · answer #4 · answered by ignoramus 7 · 0 0

I'd expect more people would answer if you asked rather than demanded.

2007-01-01 06:44:29 · answer #5 · answered by All hat 7 · 0 0

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