if f(x)=3x-8 and g(x)=square root of 2x^2+7 What is the value of f(g(3))?

Question

Is the answer 1,3,5,7,9?

Answer 1

First: find g(3) > replace 3 with the "x" variable in the "g(x)" function:

g(3) = V`[2(3)^2+7]
g(3) = V`[2(9)+7]
g(3) = V`[18+7]
g(3) = V`25
g(3) = 5

Sec: take 5 and replace it with the "x" variable in the "f(x)" function:

f(5) = 3(5) - 8
f(5) = 15 - 8
f(5) = 7

P.S. V` represents the radical sign/square root

Answer 2

7

Answer 3

g(3)=√2(3)^2+7
√2(3)^2+7
√18+7
√25
5

f(5)=3(5)-8
15-8=7

Everybody who has seven for the answer are the only ones that should be getting a thumbs up for their answer. If anyone giving them a thumbs down for that answer should redo and understand the problem again.

Answer 4

7

Answer 5

First plug in 3 for x in the g equation: 2(3^2) + 7 = 2(9) + 7 = 25 and its square root is 5
Then plug 5 in for x in the f equation: 3(5) -8 = 15-8 = 7

edited, didn't see the square root at first

Answer 6

First plug in 3 to the equation square root of 2x^2+7. Once you get that answer, plug that answer into the equation 3x-8. Just work one step at a time.

Answer 7

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Answer 8

f(g(3))=
√2(3)^2+7
√2(9)+7
√18+7
√25
5

f(5)
3(5)-8
15-8
7

Answer 9

6x^2+13