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6 answers

1) 9.6, 12.2, 14.8, and 17.4

If it requires an arithmetic sequence, then the four blanks signify there being five equal steps in the sequence fom 7 to 20. Since 20 - 7 = 13 and there are five equal steps, the steps must each be: 13 / 5 = 2.6 apart. So the blanks would be: 7 + 2.6 = 9.6 + 2.6 = 12.2 + 2.6 = 14.8 + 2.6 = 17.4 (and + 2.6 = 20).

2) 8.64, 10.65, 13.14, and 16.21

If you instead have a geomtric sequence, then the first blank is 7 times the common factor, the second blank is that times the common factor again, and so on until we reach the 20 and find it equals the 7 time the common factor five times (another way of saying the common factor raised to the fifth power). So the fifth power of that common factor equals 20 / 7 and the common factor equals the fifth root of that { (20 / 7)^0.2 } (which equals about 1.233634). If we then fill out the sequence, we get: 7 * (20 / 7)^0.2 = 8.64 * (20 / 7)^0.2 = 10.65 * (20 / 7)^0.2 = 13.14 * (20 / 7)^0.2 = 16.21 ( * (20 / 7)^0.2 = 20).

2007-01-01 05:11:07 · answer #1 · answered by roynburton 5 · 0 1

I have an answer. I don't like it but it works. The answer is that you alternate +3 and +2.

7+3=10, 10+2=12, 12+3=15, 15+2=17, 17+3=20.....

7, 10, 12, 15, 17, 20....

2007-01-01 05:14:48 · answer #2 · answered by ARM 6 · 0 0

Well... your question isn't specific enough.
We don't know what type of sequence this is. If it is an arithmetic sequence then it should look like 7, 9.6, 12.2, 14.8, 17.4, 20.

If you could provide a little more information as to what type of sequence it is...then we could help answer your question more thoroughly.

2007-01-01 05:03:26 · answer #3 · answered by Sam L 2 · 0 0

I can't prove it, but I don't think you've given enough information for that series problem to be solved. Check your math book again...

2007-01-01 04:58:16 · answer #4 · answered by plenum222 5 · 1 0

What do you want to find? An arithmetic sequence or a geometric sequence? Or neither?

2007-01-01 04:57:41 · answer #5 · answered by sahsjing 7 · 1 0

There isn't enough information here to solve this. Sorry!

2007-01-01 05:03:27 · answer #6 · answered by steiner1745 7 · 1 0

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