what is the integral of x cos x^2 dx ?

0 ⤊

2007-01-01 04:36:32 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

∫ x cos x^2 dx
= ∫(1/2)cos x^2 dx^2 (mental substitution: u = x^2)
= (1/2)sin x^2 + c

2007-01-01 04:41:36 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

Make a substitution: u = xÂ², du = 2xdx
So you get 1/2â«cos u du = 1/2 sin u + C = 1/2 sin xÂ² + C.

2007-01-01 12:44:12 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋