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2007-01-01 04:34:59 · 7 answers · asked by ,,,,,,, 2 in Science & Mathematics ➔ Mathematics
how to find the area
2007-01-01 04:35:28 · update #1
You can use Heron's formula on the triangle then just add the square.........
Semiperimeter s=(2+3+3)/2 =4 then area of triangle = sqrt(s(s-a) (s-b)(s-c)) = sqrt(4*(4-3)* (4-3)*(4-2)) = sqrt(4*2) = 2*sqrt(2). Then area of square =2*2=4 so total area is 4+2sqrt(2)
2007-01-01 04:42:34 · answer #1 · answered by a_math_guy 5 · 1⤊ 0⤋
Rotten picture, bad topic headline.
If the rectangle is supposed to be 2 cm on side and the equilateral triangle 3 cm on the equal sides, then the area of the rectangle is that of a square, 2x2, while the area of a triangle is 1/2 x Base x Height, so need Height. Triangle is 2 on bottom, so height is from formula for sides of triangle a^2 = b^2 + c^2 where a=3, b=1 (half the base) and c is the height. So the height is square root of 3^2 (9) minus 1^2 (1) or the square root of 8.
That should be enough.
2007-01-01 04:47:40 · answer #2 · answered by Mike1942f 7 · 0⤊ 1⤋
You should find the area of the square and circle separately:
1) The square's area is s^2 = 2^2 = 4 cm^2.
2) The triangle's area can be found using Heron's formula: Area = sqrt(s(s-a)(s-b)(s-c)), where s is the perimeter divided by 2 and a, b, and c are the sides. So s = (2+3+3) / 2 = 4; sqrt(4*2*1*1) = sqrt8 = 2sqrt2 or about 2.83 cm^2.
The total area is 4 + 2sqrt2 cm^2 or about 6.83 cm^2.
2007-01-01 04:45:57 · answer #3 · answered by sesquipedalian 3 · 0⤊ 0⤋
You need to find the sum of the areas of the square and the isosceles triangle.
area of the square = 2^2 = 4 cm^2
area of the triangle = (1/2)base x height = (1/2)(2)(√8) = √8 cm^2
The height is calculated from Pythagorean theorem:
h = √ (3^2 - 1^2)
total area = 4+√8 cm^2
2007-01-01 04:46:42 · answer #4 · answered by sahsjing 7 · 1⤊ 0⤋
First you can find the the area of the square.
2x2=4
Then you find the height of your triangle.
Using the Pythagorean Theorem the value of c ( the hypotenuse) is 3. The base 'a' is 1 (half of the length of the square because you need a right triangle)
a^2+b^2=c^2
1^2+b^2=3^2
1+b^2=9
b^2=8
b=sq rt 8=2.8
the area of the triangle is approx. half of 2.8*1 or 1.4
We now add the areas together and get 1.4+4=5.4
The approximate area of your figure is 5.4 cm^2
2007-01-01 04:49:19 · answer #5 · answered by tval_friedly 2 · 0⤊ 1⤋
base x hight + base x hight /2
2007-01-01 04:42:24 · answer #6 · answered by Sporkzilla 3 · 0⤊ 1⤋
find the area of the square then the triangle and then add them together
your welcome
2007-01-01 04:42:26 · answer #7 · answered by cyberturtle88 1 · 0⤊ 2⤋