1. Solutions of potassium hydroxide and propanoic acid are mixed
This is all i have so far: KOH + C3H6O2
i believe the potassium hydroxide breaks up right? into K+ OH-
2.A solution of iron (11) chloride is added to an acidified solution of sodium dicrhromate
this is what i have so far: FeCl2 + Na2Cr2O7
(all the numbers are SUBSCRIPTS!)
thanx!!
2007-01-01 04:00:59 · 3 answers · asked by trakstar16 1 in Science & Mathematics ➔ Chemistry
the oxidation number for iron is 2 not 11..sorry!
2007-01-01 04:10:10 · update #1
1. Potassium hydroxide is a base and propanoic acid is (obviously) an acid, so here you get an acid-base reaction, producing potassium propanoate.
KOH + CH3CH2COOH --> CH3CH2COO- K+ + H2O
2. I don't think you'll get iron(II) dichromate here. Remember that acidified dichromate is an oxidising agent, and although in aqueous solution iron prefers to exist in its iron(II) state, the dichromate is a stronger oxidising agent. So actually you'll get:
6Fe2+ + 14H+ + Cr2O72- --> 6Fe3+ + 2Cr3+ + 7H2O
2007-01-01 04:25:02 · answer #1 · answered by claudeaf 3 · 0⤊ 0⤋
The first reaction gives potassium propionate and water (KC3H5O2 + H2O)
The second reaction is a more complicated one involving the oxidation of iron from Fe+2 to Fe+3. The chromium is reduced from Cr+6 to Cr+3
6FeCl2 + Na2Cr2O7 + 14 H+Cl- ==> 6FeCl3 + 2CrCl3 + 7H2O + 2 NaCl
Be sure to check my work to insure that the equation is balanced.
(Note: it would sure help if this editor would allow for subscripts and superscripts) BTW: Dichromate is a strong oxidizer, especially in acid solution. I supplied the acid (HCl)
Rots of Ruck :>)
2007-01-01 12:22:30 · answer #2 · answered by docrider28 4 · 0⤊ 0⤋
KOH + CH3CH2COOH---> KCH3CH2COO + H2O
potassium propanate
FeCl2+ Na2CrO4 ---> FeCrO4 + 2NaCl
2007-01-01 12:06:53 · answer #3 · answered by science teacher 7 · 0⤊ 0⤋