Thousands, millions or billions?
2007-01-01 03:21:27 · 9 answers · asked by pcnut4u 2 in Science & Mathematics ➔ Mathematics
10 x 10 x 10 x 10
10,000 because there can be 10 possibilities for the first number, then the second number offers 10 more possibile combinations per each of the first single possibility, and so on and so on. This is a simple solution to the problem of possibilities. When you add in the possibility of using letters (both CAPITAL and lower case) the number jumps tremendously.
There would be 10 numbers and 52 letters possible for the first character ( 62 possibilities). Substitute the 10's in the opening equation with 62's and you will discover how many more possibilities there can be. And that doesn't even include special characters, of which I don't know how many there may be.
2007-01-01 03:33:36 · answer #1 · answered by tercir2006 7 · 0⤊ 0⤋
While all the previous "yahoos" ;) are quick to say "10,000", they are only right if the PIN "number" consists of numbers 0 to 9 in each digit.
The total number of possibilities is equal to the number of possibilities for each digit raised to the 4th power, assuming the possibilities are the same, or the number of possibilities for each digit multiplied together, in the general case.
Say the possibilities are letter A thru Z (26 letter alphabet, here) The number of possibilities is 26*26*26*26=456976
If it were three digits of 0-9 and one of A-Z, it would be 10*10*10*26=26000
2007-01-01 04:06:24 · answer #2 · answered by Ron E 5 · 0⤊ 0⤋
You have ten possibilities for each digit. So you've got 10*10*10*10 total possibilities, that's 10,000.
2007-01-01 03:29:05 · answer #3 · answered by InitialDave 4 · 0⤊ 0⤋
10,000 is correct, as others have answered. And thank you for not saying "pin number" as many (most) do.
2007-01-01 03:45:08 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Lets count them shall we?
0000
0001
0010
0100
1000
0011
1100
1001
0110
1010
0101
1111
Bored Yet? And thats just using 1s and 0s, I don't think anyone has figured out the full number, it would take too long.
2007-01-01 03:29:58 · answer #5 · answered by ukcufs 5 · 0⤊ 4⤋
You never say how many times you could use each digit.
If you use each digit once then there are 10,000 options.
If you use each digit more then once, then you have more options.
2007-01-01 03:25:29 · answer #6 · answered by Brenmore 5 · 0⤊ 5⤋
Exactly 10,000.
2007-01-01 03:24:33 · answer #7 · answered by Anonymous · 1⤊ 0⤋
10x10x10x10 = 10,000
2007-01-01 03:28:45 · answer #8 · answered by Susan S 7 · 0⤊ 0⤋
there are 1679616 possibilities
2007-01-01 03:46:16 · answer #9 · answered by Anonymous · 0⤊ 5⤋