Two cards are drawn from a standard 52 card deck. What is the probability that they will be the same suit?
How is the answer: "12/51"?
2007-01-01 01:27:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
you pick one card first, it will be one of the 4 suits
whichever suit the first card it, there will be 12 cards of that suit left in the deck of 51 cards, so you have a 12/51 chance of picking one of those cards
2007-01-04 19:47:46 · answer #1 · answered by Anonymous · 0⤊ 0⤋
There are 13 cards of each suit and 52 cards in the deck.
After you draw the first card, there are 51 cards left and 12 of them are the same suit as the first card.
That's how you get 12/51.
The probability that the next card would be the same suit is 11/50.
The probablity of a five-card flush (all five the same suit) is (12*11*10*9) / (51*50*49*48) or about 0.2%
2007-01-01 09:32:41 · answer #2 · answered by Steve A 7 · 1⤊ 1⤋
Like Steve said, so a big point in the background is that the first card doesn't matter ! ! ! ! ! Spades, hearts, clubs, diamonds, it doesn't matter! The first card (whatever suit it is) just determines what the second suit has to be for a match. Then of course the 12 part is that one of the suit of 13 has already been picked so there are 12 of (whichever) suit remaining and the 51 part is how many cards remain.
2007-01-01 11:12:57 · answer #3 · answered by a_math_guy 5 · 0⤊ 0⤋
probability that the 2 cards drawn are the same suit = 13/52 x 12/51
= 0.0588
2007-01-01 09:37:07 · answer #4 · answered by Anonymous · 0⤊ 2⤋
now that we have taken one card(can be any suit)
number of cards remaining = 51
number of cards of the suit = 12(same as 1st one card removed)
so probability that card shall be of the suit = 12/51
2007-01-01 09:34:43 · answer #5 · answered by Mein Hoon Na 7 · 1⤊ 0⤋