Puzzles.....
2007-01-01 00:33:02 · 7 answers · asked by Fahd 2 in Science & Mathematics ➔ Mathematics
(a) 3! / (3 + 3) = 1
(b) (3! - 3) / 3 = 1
(c) 3 - (3!/3) = 1
(d) (3 + 3) / 3! = 1
2007-01-01 02:12:57 · answer #1 · answered by Anonymous · 4⤊ 0⤋
(3/3)^3 = (1)^3 = 1
2007-01-01 08:38:06 · answer #2 · answered by Faraz S 3 · 1⤊ 0⤋
3^(3-3) = 3^0 = 1
2007-01-01 09:40:10 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋
3! / (3 + 3) = 1
(3! - 3) / 3 = 1
3 - (3!/3) = 1
(3 + 3) / 3! = 1
3^(3 - 3) = 1
(3 / 3)^3 = 1
2007-01-05 03:41:21 · answer #4 · answered by hanumistee 7 · 0⤊ 0⤋
(3/3)^3
2007-01-01 08:44:28 · answer #5 · answered by Nitin T F1 fan 5 · 1⤊ 0⤋
(3!-3)/3=1
That's 3 factorial (1*2*3) minus 3 all divided by 3
2007-01-01 08:59:10 · answer #6 · answered by Michael C 1 · 0⤊ 0⤋
(3/3)^3 = 1
That's three divided by three, all to the third power.
2007-01-01 08:37:52 · answer #7 · answered by Anonymous · 1⤊ 0⤋