What do you understand by average nuclear binding energy per nucleon? Explain the implications for the stability of a given nuclide of a high value of the average binding energy per nucleon. Sketch a binding energy curve and indicate the region of maximum nuclear stability.
2006-12-31 22:46:19 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
you dont expect me to do you homework!!
anyways.. i'll explain it briefly.. the binding energy is the energy that electrons face in terms of force of attraction towards the nucleus. in radioactive reactions, it's actually the outermost electrons that are 'knocked out' from their orbits (radioactive decay!) so the more an atom experiences force of attraction from the nucleus, the more energy would be required to knock it out since it would be more difficult to throw it out of that field created around it. this means that the atom would be more 'stable', i.e, less likely to act in a volatile method and requiring much more energy to cause a radioactive decay!
hope that helps!
2006-12-31 23:10:33 · answer #1 · answered by Shariq M 5 · 0⤊ 0⤋
Binding energy is the difference between the mass of an atomic nucleus and the mass of the constituent nuclei. A measure of nuclear stability. In other words, it is the energy released when the nucleus of an atom is formed by combining neutrons and protons.
By having a high binding energy per nucleon, this indicates a high stability such as 56Fe
A binding curve can be found here.
http://en.wikipedia.org/wiki/Binding_energy
The region of maximum nuclear stability is therefore the region whereby the binding energy per nucleon is the highest at 56Fe.
2007-01-01 01:10:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋