I need help with the following question: If 9% of an African population is born with a severe form of sickle-cell anemia (ss), what percentage of the population will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene?
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please list steps so I can understand this better?
2006-12-31 17:16:46 · 1 answers · asked by Anonymous in Education & Reference ➔ Homework Help
If one homozygous extreme of the punnet square (ss) is 9%, I would imagine that the other homozygous extreme (SS) would also be 9%. Since all other combinations would be heterozygous (Ss), 82% of the population would be more resistant "because they are heterozygous." However, technically speaking, 91% (82% Ss + 9% SS) of the population would be more resistant because they have at least one zygote that combats against the sickle cell gene.
2006-12-31 18:33:12 · answer #1 · answered by J D 2 · 0⤊ 0⤋