CH4(g) + O2 --> CO2(g) + H2O + energy
I was also wondering if the enery that is with the H20 makes any difference in balancing the equation. Thanks.
2006-12-31 14:12:51 · 6 answers · asked by ╦╩╔╩╦ O.J. ╔╩╦╠═ 6 in Science & Mathematics ➔ Chemistry
CH4(g) + 2O2 --> CO2(g)+2 H2O+ energy
i dont think that the energy doesn't do anything
2006-12-31 14:20:01 · answer #1 · answered by Anonymous · 1⤊ 0⤋
CH4(g) + 2 O2 --> CO2(g) + 2 H2O + energy
the answer to ur other question....no, its not with the H2O, the energy is just another one of the products (everything to the right of the arrow)
2006-12-31 22:15:50 · answer #2 · answered by kat_suzz 2 · 1⤊ 0⤋
1 methane
2 water
1 carbon dioxide
2 oxygen
The energy involved won't change the coefficients you need to put in front of the chemicals involved in the equation.....
but.....
the energy you get when you burn 1 mole of methane is known as methane's "heat of combustion". There are cases (and I don't think you're there yet), where if you need to double or triple everything in an equation to calculate a heat of reaction, then the energy would also get doubled or tripled.
2006-12-31 22:23:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Hi!
What I get is this:
CH4 + 2O2 --> CO2 + 2H2O + Energy
Well, I do not think that the energy has any affect.
I hope I helped and Happy New Year 2007!
Asker K
2006-12-31 22:16:55 · answer #4 · answered by Mr Asker Knowmore 2 · 1⤊ 0⤋
CH4 +2 O2 --> CO2 +2 H2O + energy
L.H.S
C=1
H=4
O=4
R.H.S
C=1
H=4
O=4
yes but you would need to invoke nuclear synthesis :)
??(g)
2006-12-31 22:23:55 · answer #5 · answered by mathman241 6 · 0⤊ 0⤋
Yes, I can!!!
Just in case you're interested the balanced equation is
2CH4 + 4O2 = 2CO2 + 4H2O
2006-12-31 22:26:46 · answer #6 · answered by Lee 2 · 0⤊ 0⤋