I'm wonderin', i never did find out about a for solving logarithms da easy way. By the way, this question is log with 3 on the bottom and the 3 on top. The answer is 2, i'm sure.
2006-12-31 13:55:23 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I dont know about a log 3 on the bottom.
It is ususally put liker this
3
...log 38
this means that the base is 3, so you have to find a number x such that 3^x = 38
There is no way of doing this by hand unless for some special numbers the numbers . , that is when the argument of the log is a power of a quotient ( or integer number )
3
.log (3^5) = 5
2006-12-31 18:14:20 · answer #1 · answered by gjmb1960 7 · 0⤊ 0⤋
Do you mean log(base 3) of 3? that would be 1, because 3^1 = 3.
In general, when you ask about logs, you need a base. If no base is stated, base 10 is understood. So when I saw log 38, I thought of, what number do you need to raise 10 to, to get 38? No whole or rational number, certainly, but it can still be done. Just enter it into your calculator (before we had calculators we used log tables) and youll find that log of 38 ~= 1.57978
Now try entering into your calculator 10^1.57978 and you'll get 37.999999999999 that's because you rounded off the number. If you use more digits behind the decimal point you'll get better accuracy. If you use enough you'll exceed the tolorances of the calculator and you'll get 38.
Try this ... rather than re-entering 1.57978, just do log 38, and keep that number in the display register.
Then do 10^(ans) if your calculator has an answer key, and you should get back to 38
I like to say, logs are exponents, even tho that's a bit of an oversimplification. Actually, logs are functions which return the exponent of the arguement, in terms of the base. But to say, logs are exponents, helps people to understand how the laws of logs correspond to the laws of exponents.
A lot of people have trouble understanding logs, you have to kind of "think backwards" because they're an inverse function, the inverse of the exponential function. It takes practice. I suggest you find a tutorial website and work with it for a while.
For starters, try this one:
http://www.lecb.ncifcrf.gov/~toms/paper/primer/latex/node2.html
or if that doesn't do it for you, put tutorials logarithm in your search window and check what comes up.
2006-12-31 13:58:03 · answer #2 · answered by Joni DaNerd 6 · 1⤊ 0⤋
log(4-w) = log(2w^2+7w-38) 4-w = 2w^2 + 7w - 38 2w^2 + 8w - 40 2 = 0 w^2 + 4w - 21 = 0 (w+7)(w-3) = 0 w = -7 or w = 3 because the logarithmic expressions above are defined for both those values of w, they're both valid thoughts.
2016-12-01 09:24:33 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Something is wrong.
log₃9 = 2
but log₃8 ≠ 2
2006-12-31 14:04:52 · answer #4 · answered by sahsjing 7 · 2⤊ 0⤋
I am not clear what you are really asking but I will guess
If you are trying to evaluate the logarithm base 3 of 3 to the eighth power then the answer is 8
I can not think of what other valid interpretation I can make. My guess has ignored your "3 on top" statement.
2006-12-31 15:11:27 · answer #5 · answered by anonimous 6 · 0⤊ 0⤋
Do you mean log[base 3](8) or log[base 3](38)?
2006-12-31 13:58:01 · answer #6 · answered by Puggy 7 · 1⤊ 1⤋
Not clearly asked
2006-12-31 13:59:52 · answer #7 · answered by Sheen 4 · 2⤊ 0⤋
Very poorly stated question.
Reprase it....CLEARLY...in plain english with sifficient detail and maybe someone will understand you enough to respond with an appropriate answer.
2006-12-31 14:05:57 · answer #8 · answered by Anonymous · 4⤊ 2⤋
change of base formula... look it up
2006-12-31 14:03:42 · answer #9 · answered by Baljinnyam D 1 · 0⤊ 0⤋
log (subscripta) b^c
means that ca=b
2006-12-31 14:00:12 · answer #10 · answered by Paul B 3 · 0⤊ 2⤋