2006-12-31 12:08:27 · 3 answers · asked by godisgreat 1 in Science & Mathematics ➔ Chemistry
Fe(CO5)
let oxidation state of fe be
oxidation state of C = +4
oxidation state of O = -2
therefore
x+(+4)+5(-2)=0 (total oxidation state of neutral compound is zero )
x+8-10=0
x - 2 = 0
x = 2
oxidation state of Fe in Fe(CO5) is +2
2007-01-01 21:33:22 · answer #1 · answered by kainesh p 2 · 0⤊ 8⤋
oxidation state of Fe in Fe (CO5) is 0 because CO is a neutral ligand and does not contribute to charge so Fe is in its natural state with oxidation number = 0
2006-12-31 14:20:05 · answer #2 · answered by WILLIAM V 1 · 8⤊ 0⤋
It is 0. The valence is 5. The confusion is that oxidation numbers are an arbitrary system of bookkeeping useful for balancing oxidation-reduction equations, but for nothing else. They have no physical significance. Oxidation numbers sometimes coincide with valences.
2006-12-31 12:23:59 · answer #3 · answered by steve_geo1 7 · 3⤊ 0⤋