2006-12-31 11:39:39 · 17 answers · asked by meee 2 in Pregnancy & Parenting ➔ Newborn & Baby
yep they miss the tax cut off for the previous year
2006-12-31 11:42:05 · answer #1 · answered by dianehaggart 5 · 0⤊ 0⤋
Not any more special than any other baby. It is just a holiday that is all. All babies are special
2006-12-31 19:41:54 · answer #2 · answered by celestial_fantasia 3 · 0⤊ 0⤋
My nephew turned 3 today...he is a new year's eve baby...and he's special...because he's my nephew... didn't matter what day he was born.
It's a pain that his birthday party is always the afternoon of new year's eve...but we all go to his party just the same.
Happy 3rd Birthday Donovan !!!!
2006-12-31 21:20:18 · answer #3 · answered by amanacer99 2 · 0⤊ 0⤋
Not really. I know someone who was born on New Years. And trust me, they are not that special. haha :] A bit loud, but not special or talented in anyway XD
2006-12-31 19:47:56 · answer #4 · answered by J 2 · 0⤊ 0⤋
my cousin was born on new years eve, and he hated it growing up. Now 19, he doesn't mind it though as everyone's up to go out and party. I dont think they're any more special than anyother baby
2006-12-31 19:44:47 · answer #5 · answered by Anonymous · 0⤊ 0⤋
All babies are special
2006-12-31 19:40:56 · answer #6 · answered by ra63 6 · 1⤊ 1⤋
Some cities have contests with cash prizes for the first born child of the new year. Try a google search.
2006-12-31 19:42:45 · answer #7 · answered by barkel76 4 · 1⤊ 0⤋
I guess the first one born in the new year is special,not the rest though..haha!
2006-12-31 19:41:24 · answer #8 · answered by molliehollie 7 · 0⤊ 0⤋
Of course! They are the first babies of the year!
2006-12-31 20:22:43 · answer #9 · answered by ShaMayMay 5 · 0⤊ 0⤋
Yes because they were born on the first day of the new year!
2006-12-31 19:40:58 · answer #10 · answered by Trapped in a Box 6 · 0⤊ 0⤋
all b abies are special but usually the one born 1st in the new year gets paid attention to in the local papers...
2006-12-31 22:45:26 · answer #11 · answered by diane b 3 · 0⤊ 0⤋