A solution contains the ions Ag+, Pb2+, and Ni2+. Dilute solutions of NaCl, Na2SO4, and Na2S are available to separate the positive ions from each other. In order to effect separation, the solutions should be added in which order? A) Na2SO4, NaCl, Na2S B) Na2SO4, Na2S, NaCl C) Na2S, NaCl, Na2SO4 D) NaCl, Na2S, Na2SO4 E) NaCl, Na2SO4, Na2S
Answer and Explain why! Thanks.
2006-12-31 11:10:15 · 2 answers · asked by sunneyzwang@sbcglobal.net 2 in Science & Mathematics ➔ Chemistry
Use the sequence E (NaCl, Na2SO4, then Na2S). Silver is insoluble as a chloride, so it would be removed first, the others (Pb and Ni) are soluble as chlorides(Note; lead chloride is soluble as a hot solution but will ppt when cold), next, PbSO4 is insoluble but NiSO4 is soluble so use Na2SO4 to separate lead from nickel. Lastly, nickel sulfide is insoluble and can be separated and collected.
2006-12-31 11:48:33 · answer #1 · answered by docrider28 4 · 5⤊ 0⤋
See the following site for reactivity chart and explanation of why:
http://dbhs.wvusd.k12.ca.us/webdocs/Equations/Solubility-Table.html
(All other solubility tables say that silver sulfate is soluble)
Add Na2SO4 first...lead (Pb) will ppt
Add NaCl second...silver (Ag) will ppt
Add Na2S last to ppt the nickel
2006-12-31 11:56:55 · answer #2 · answered by teachbio 5 · 2⤊ 0⤋