This is the question:
Adrenaline is the hormone that triggers release of extra glucose molecules in times of stress or emergency. A solution of 0.64 g of adrenaline in 36.0 g of CCl4 elevates the boiling point by 0.49°C. What is the molar mass of adrenaline?
I found the moles of CCl4 [36 g/154 g-mol CCl4]. Then I did .64 g adrenaline/moles of CCl4, but I got the answer wrong.
So now I'm thinking... should I find the chemical compostion and formula weight of adrenaline and then just do .64 g adrenaline/moles adrenaline? Is the CCl4 irrelevant?
2006-12-31 10:42:16 · 3 answers · asked by SDesign 1 in Science & Mathematics ➔ Chemistry
Alright, now I'm totally lost. The answer is still wrong.
2006-12-31 11:00:03 · update #1
Okay... molar mass is eqaul to grams/mole. Right? .64 Mole / FW of Adrenaline... the answer is still wrong.
2006-12-31 12:59:58 · update #2
trick quesiton. Look at the bottom line: "What is the molar mass of adrenaline". You know how to do that, right? That's the only question remaining (the temp. info is a distraction).
2006-12-31 12:58:17 · answer #1 · answered by Promicarus 2 · 0⤊ 0⤋
You need to look up the Kb (boiling constant) for carbon tetrachloride. Then apply the formula.
delta Bp = Kb x m
m = molality = moles/kg (mols/1000g)
moles = (delta Bp x 1000)/Kb
convert 0.64g adrenaline/36 g CCl4 to GRAMS per 1000gCCl4
solve for GRAMS per mole
2006-12-31 11:40:35 · answer #2 · answered by docrider28 4 · 0⤊ 0⤋
Yep you got it
2006-12-31 10:51:32 · answer #3 · answered by simon c 2 · 0⤊ 0⤋