How do I find the magnatude of vector (-7,6) and (2,3) and leave it in simple radical form????

Answer 1

It's the same as using the distance formula:
d=√(x2-x1)^2+(y2-y1)^2
√(2+7)^2+(3-6)^2
√(9)^2+(-3)^2
√81+9
√90 or 3√10

Answer 2

How do I find the magnatude of vector (-7,6) and (2,3) and leave it in simple radical form????

Ithink you are asking what is the magnitude of the sum of the vector (-7,6) and the vector) (2,3).
If this is correct , then sum of vectors = (-7+2, 6+3)= (5,9).
The magnitude of vector (5.9) is:
sqrt(5^2+9^2) =sqrt (25 +81) = sqrt (106)
That's as simple as you can make it.

Answer 3

Magnitude is the length of a vector, which is calculated as
sqrt[x^2 + y^2]

Distance between vectors:
sqrt[(x2 - x1)^2 + (y2 - y1)^2]

I think what you're asking is the length of EACH of the vectors, but in the case you're asking for the distance BETWEEN the vectors, that can be figured out using the distance formula.

Using the magnitude formula and the point (-7,6):
x = -7
y = 6

sqrt[x^2 + y^2]
= sqrt[(-7)^2 + (6)^2]
= sqrt[49 + 36]
= sqrt[85] which cannot be simplified further as it already is.

Answer 4

x=-7-2=-9
y=6-3=3

Calculate a hypotenuse of right triangle of sides -9, 3

a^2+b^2=c^2
(-9*-9)+(3*3)=c^2
81+9=c^2
c=Squareroot of 90 = 3*sqrt(10)

this is the magnitude of the vector

Answer 5

Use the distance formula! sqrt((2--7)^2+(3-6)^2)

Answer 6

use distance formula..

you take (3-6)^2
and (2-(-7))^2
this gives 9 and 81, and add the two squared numbers.. to get 100, take square root to get 10

no radical left.... perfect square... has perfect root..;)