I keep getting -2/7 and I don't know what else I am supposed to be doing
thank you
2006-12-31 07:09:55 · 6 answers · asked by emerydrame 1 in Science & Mathematics ➔ Mathematics
-2/7 is the slope of the line connecting the two points, which you computed.
The slope of every perpendicular line is 7/2 (the negative of the inverse of the slope).
So, every line that is perpendicular has the form y = mx + b
where m, the slope, is 7/2
So y=7/2x + b is a formula for evey line that is perpendicular to the line connecting your two points.
"b" can be anything.
2006-12-31 07:18:53 · answer #1 · answered by firefly 6 · 2⤊ 0⤋
To solve this problem, you have to find the slope of the line. The slope can be found by using the formula, second y value(1) minus the first(3) over the second x value(5) minus the first(-2), or (ysub2 - ysub1)/ (xsub2 - xsub1). So (1-3)/(5+2)= -2/7, which is the slope. A perpendicular line is any that has a slope that is the opposite reciprocal of the original lines slope. A line with the slope 7/2 is perpendicular to the first line. Use the values and and the point-slope formula to find the equation of the perpindicular line.
2006-12-31 07:23:00 · answer #2 · answered by Sean 2 · 2⤊ 0⤋
First: find the slope by placing the pts in the slope formula >
>> m = (second y - first y)/(second x - first x)
m = 1-3/5-(-2)
m = -2/7
Second: place the slope (-2/7) and one set of pts (5,1) in the slope-intercept formula to find the y-intercept ("b"):
y = mx + b
1 = (-2/7)(5) + b
1 = -10/7 + b
1 + 10/7 = -10/7 + 10/7 + b
17/7 = b; b = 17/7
Third: a perpendicular line has the opposite slope of (-2/7) which is 7/2. Place 7/2 and the y-int (17/7) in the slope-intercept formula.
y = 7x/2 + 17/7
2006-12-31 09:29:56 · answer #3 · answered by ♪♥Annie♥♪ 6 · 3⤊ 0⤋
Here is what I would do to find the answer to that question:
a) Determine the slope of the line containing those points.
b) Determine the slope perpendicular to that found in (a).
Note: There are an infinite number of lines perpendicular to the line containing your two given points.
a) m = (y2 - y1)/(x2 - x1) = (1 - 3)/(5 - (-2)) = -2/7
b) Perpendicular means that the slopes are NEGATIVE RECIPROCALS.
The negative reciprocal of -2/7 is 7/2.
7/2 is the slope of the line you're looking for.
The equations of the lines that have a slope of 7/2 is y = (7/2)x + b.
2006-12-31 07:20:37 · answer #4 · answered by purpicita_LM_es_fg_MDK 2 · 3⤊ 0⤋
Your first step is to find the slope, here's the formula:
Slope:
m=(y2-y1)/(x2-x1)
m=(1-3)/(5+2)
m=-2/7
Here's the next step:
(y-y1)=m(x-x1)
(y-3)=-2/7(x+2)
y-3=-2/7x-4/7
y=-2/7x+17/7
The perpendicular of that line is this:
y=7/2x+17/7
2006-12-31 07:14:36 · answer #5 · answered by Anonymous · 2⤊ 1⤋
Firstly.. your required slope is the negative reciprocal of the slope between the points.
once you have the slope, 7/2
use the point slope formula..
y-y1=m(x-x1)
to get your equation of line.. where x1,y1 is a point. pick one of the given points.
you can do the rest...
2006-12-31 07:16:53 · answer #6 · answered by JAC 3 · 4⤊ 0⤋