2006-12-31 06:17:06 · 20 answers · asked by jemba 3 in News & Events ➔ Current Events
Technically speaking, 2006.
The ball drops the length of the tower above 1 Times Square, but (and this can be verified by video playback) there is a 0.5 second delay between the ball completing it's drop and the 2007 sign lighting up. Therefore the ball finishes it's drop at 23:59:59.5 EST on New Year's Eve!
Slight Addenum if I may: Consulting my recordings of the 2007 ball drop, I'd like to post the timings as determined by a DVD recording. Between the time of 23:59 and 00:00, there are 25 frames of video images. The time between the ball completing it's drop and the 2007 sign being switched on is six, this means that there is a 0.25 second gap between the ball dropping and the lights being switched on. Therefore the ball drops at 23:59:59.75 on New Year's Eve 2006
2007-01-01 12:04:21 · answer #1 · answered by Harry Hayfield 6 · 0⤊ 1⤋
2007
2006-12-31 06:27:29 · answer #2 · answered by ckm1956 7 · 1⤊ 0⤋
2007
2006-12-31 06:20:03 · answer #3 · answered by Kandy 6 · 1⤊ 0⤋
2007
2006-12-31 06:19:06 · answer #4 · answered by Anonymous · 2⤊ 0⤋
2007
2006-12-31 06:19:01 · answer #5 · answered by Anonymous · 2⤊ 1⤋
2007
2006-12-31 06:18:31 · answer #6 · answered by je t'♥ 5 · 2⤊ 1⤋
2007 !
2006-12-31 06:20:19 · answer #7 · answered by Anonymous · 1⤊ 0⤋
Well, it's supposed to start out in 2006 and land in 2007, but one year it totally got stuck and the bugger came down a few seconds too late and totally screwed up poor Dick Clark's countdown.
2006-12-31 06:25:23 · answer #8 · answered by fizzygurrl1980 7 · 2⤊ 0⤋
2007 on the East Coast.
2006-12-31 06:21:58 · answer #9 · answered by redwidow 5 · 1⤊ 0⤋
2007. It lands after the countdown
2006-12-31 06:19:20 · answer #10 · answered by kinkyafro22 2 · 2⤊ 0⤋