xy=8, so x =8/y, y can not be zero.
x + y = 6
(8/y) + y =6
8 + y^2 = 6y
y^2 -6y + 8 = 0
(y-4)(y-2)=0
y = +4 or y=+2
x=2, y=4; and x=4, y=2
2006-12-31 04:30:40
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answer #1
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answered by fcas80 7
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You can do this in your head xy = 8
x + y = 6
It should be readily seen that the answers are 2 and 4
cause 2 x 4 + 8 AND 2 + 4 = 6
2006-12-31 08:16:53
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answer #2
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answered by David C 2
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First: take either equation and solve for "x" or "y" ...let's take the first equation and solve for "y." Divide both sides by "x" and keep "y" on one side:
xy = 8 >
(xy)/x = 8/x
y = 8/x
Second: take 8/x and replace it with the "y" variable in the second equation. Get rid of the fraction: take the denominator and multiply it by everything:
x + 8/x = 6
x(x) + x(8/x) = x(6)
x^2 + 8 = 6x
Third: set the equation to equal "0" and factor. Take both sets to equal "0" and solve for "x" variables:
x^2 - 6x + 8 = 6x - 6x
x^2 - 6x + 8 = 0
(x - 4)(x - 2) = 0
x - 4 = 0
x - 4 + 4 = 0 + 4
x = 4
x - 2 = 0
x - 2 + 2 = 0 + 2
x = 2
x = 2, 4
2006-12-31 10:23:41
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answer #3
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answered by ♪♥Annie♥♪ 6
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when x=4,y=2 and when x=2,y=4
2006-12-31 04:31:01
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answer #4
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answered by fernando 1
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You will not do well in your exams if you ask for all your answers without thinking about the question. I have just ask my 9 year old and he answered very quickly 2,4. Always look for the factors of the answer when you have an xy equation
2006-12-31 06:28:04
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answer #5
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answered by jewelking_2000 5
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y=8/x
x+8/x=6
x^2-6x+8=0
x=4 or 2 substituing this in equation
y=4 or 2
the answer is
X is either 4 or 2
Y is either 4 or 2
2006-12-31 04:50:53
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answer #6
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answered by Suhas 2
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4*2=8
4+2=6
The answer is 4 or 2
2006-12-31 04:35:31
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answer #7
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answered by john doe 2
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x^2-6x+8=0
(x-2)(x-4)=0
x-2=0
x1=2
x-4=0
x2=4
2006-12-31 04:33:26
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answer #8
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answered by iyiogrenci 6
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So, how's YOUR homework going?
2006-12-31 04:30:53
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answer #9
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answered by Anonymous
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4,2
2006-12-31 04:28:07
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answer #10
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answered by Anonymous
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