The mass of a metal cylinder varies jointly as its height and the square of the radius of its base. One cylinder has a mass of 120 g. Find the mass of a second cylinder made of the same metal, 3 times as high, and having one-half the base radius of the first.
2006-12-31 04:23:12 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Volumes for Cylinders 1 and 2:
V1 = Pi(R^2)xH
V2 = Pi(R/2)^2 x 3H = (Pi(R^2)/4)x3H)
V2/V1 = [Pi(R^2)/4)x3H]/[Pi(R^2)xH] =3/4
V2 = (3/4) V1
Since Mass = density x volume and density is a constant, The mass of volume 2 is 3/4 the mass of volume 1.
3/4(120) = 90
2006-12-31 04:46:16 · answer #1 · answered by nospamcwt 5 · 0⤊ 0⤋
90 g
2006-12-31 04:27:51 · answer #2 · answered by balakrishnan 1 · 0⤊ 0⤋
1/4*3*120g=90g
Basic equation r^2(pi)* height, because height is increased 3 times you multiple 3, and because it is r^2 and radius is decreased by half you multiple (1/2)^2 or 1/4
lol thanks nospam
2006-12-31 04:26:19 · answer #3 · answered by jdansng 2 · 1⤊ 1⤋
(3*120)/4=(3*30)=90
90 grams.
2006-12-31 04:30:32 · answer #4 · answered by _LEV_ 2 · 0⤊ 1⤋