School Sucks
2006-12-31 03:53:06 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
648 = 2*2*2*3*3*3*3 =2^3 * 3^4
This are the prime factors since 2 and 3 both are prime numbers.
2006-12-31 03:58:09 · answer #1 · answered by Som™ 6 · 0⤊ 0⤋
648 = 2^3 * 3^4
2006-12-31 11:57:32 · answer #2 · answered by James Chan 4 · 1⤊ 1⤋
2*2*2*3*3*3*3
2006-12-31 12:38:40 · answer #3 · answered by john doe 2 · 0⤊ 0⤋
That's the third time that question has come up recently:
http://answers.yahoo.com/question/index;_ylt=Al_2cVppSbvMFq6WyaWMM7gjzKIX?qid=20061227143648AAIhuxH
http://answers.yahoo.com/question/index;_ylt=AmBiKKpfpk1_tHaqR3dNTMojzKIX?qid=20061228072732AAmQ8qO
Are you guys in the same class?
Anyway, 648 = 8 x 81 = 2x2x2x3x3x3x3 = 2³ x 3^4
2006-12-31 11:58:07 · answer #4 · answered by Jim Burnell 6 · 0⤊ 0⤋
in order to solve similar problems, note that this is an even number (divisible by 2)....starts there and then keep dividing by 2 until you can't anymore.
There is a cool trick you can use...if the digits of a number add up to 9, then they are divisible by 3.
648/2= 324 (still even, so divide by 2 again)
324/2= 162 (still even, so divide by 2 again)
162/2= 81 (digits add up to 9 so divide by 3)
81/3= 27 (digits add up to 9 so divide by 3)
27/3= 9 (digit add up to 9 so divide by 3)
9/3= 3 (divide by 3)
3/3= 1
look at your divisors...2*2*2*3*3*3*3...use your calculator to double-check
You can do this....math ROCKS!
2006-12-31 12:05:02 · answer #5 · answered by teachbio 5 · 1⤊ 0⤋