{5x+2y=8 {x+y=1?

Question

thank you

Answer 1

x = 1 - y

5(1 - y) + 2y = 8

5 - 5y + 2y = 8

-3y = 3

y = -1

x = 1 - y = 1 - (-1) = 2

Answer 2

First: take either equation and solve for "x" or "y"... let's solve for "y" in the 2nd equation:

x -x + y = -x + 1
y = -x + 1

Sec: take "-x+1" and replace it the "y" variable in the 1st equation:

5x + 2(- x + 1) = 8
5x + 2(-x) + 2(1) = 8
5x - 2x + 2 = 8
3x + 2 = 8

*Subtract 2 from both sides:
3x + 2 - 2 = 8 - 2
3x = 6

*Divide both sides by 3:
3x/3 = 6/3
x = 2

Third: take the value (2) and replace it with the "x" variable in the 2nd equation:

2 + y = 1

*Subtract 2 from both sides:
2 - 2 + y = 1 - 2
y = -1

(2 , -1)

Answer 3

x = 2, y = -1

Answer 4

5x+2y=8(eqn1)
x+y=1
=>2x+2y=2(eqn2)
subtracting eqn1 from 2
3x=6
=>x=6/3=2
x+y=1
putting the value of x we get
y=1-x=1-2=-1

Answer 5

x+y = 1 => 2(x+y) = 2 => 3x + (2x+2y) = 3x + 2 = 8 => 3x = 6 => x = 2 => y = 1 - 2 = -1.

So answer x = 3 and y = -1.

Answer 6

X= 2
Y= -1

Answer 7

5x+2y=8 -------equation 1
x+y=1
y=1-x ---------equation 2

substitute 1 into 2
5x+2(1-x)=8
5x+2-2x=8
3x=6
x=2
y=1-x
y=-1

x=2,y=-1 or x=-1,y=2

Answer 8

These are both equations of lines. The place where they intersect is the solution. For that place, you will have the same numbers that work in both equations. You can find this graphically, numerically, or algebraically.

For the algebraic solution, you can change the equation on the right to y = 1-x and then substitute that in for "y" in the equation on the left. Solve for x and then find what why has to be when that is your x.

Answer 9

5x+2y=8
x=1-y
subs
5(1-y)+2y=8
5-5y+2y=8
-3y=3
y=-1
subs
x=1-(-1)=2
the solution set {2,-1}

Answer 10

5x+2y=8
x+y=1
y=1-x
5x+2[1-x]=8
5x+2-2x=8
3x=6
x=2
y=-1