it is a question from electricity.
2006-12-31 02:07:14 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The answer would depend on the circuit. If it is a constant current circuit, then since P = VI , doubling V will just double the power. If the circuit has a load resistor R then since P = V^2/R doubling V will increase the power by 4.
2006-12-31 02:11:20 · answer #1 · answered by rscanner 6 · 3⤊ 0⤋
power = potential difference*current
so power is directly proportional to potential difference
so when potential difference is increased by 2 times the power becomes double
2007-01-04 06:19:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
P = V I
V/P = 1/I
If the current is the same, then power will be doubled, if voltage is doubled
P = V ^2/ R
V^2 /P = 1/R
If the resistance is the same, then power will be increased four times, if voltage is doubled
2006-12-31 11:40:09 · answer #3 · answered by Pearlsawme 7 · 0⤊ 0⤋
p=v^2i
so doubling the pot. diff. will make the power to increase by four times
2006-12-31 10:49:14 · answer #4 · answered by abhi-avi 3 · 0⤊ 0⤋
power = (current)^2*resistance
current^2 =pot diff^2/resistance^2
therefore if pot diff is increased by 2
power is increased by 4
2006-12-31 14:31:10 · answer #5 · answered by hellraiser 2 · 0⤊ 0⤋
Power=Volts*Amps
=V. I
=V*V/R
=V^2/R
So if voltage is doubled
power will be quadrupled.
What was P will become 4P
2006-12-31 10:12:45 · answer #6 · answered by openpsychy 6 · 2⤊ 0⤋
friction is buyproduct of energy
2006-12-31 12:23:31 · answer #7 · answered by nexttend 1 · 0⤊ 0⤋