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4 answers

The first response is absolutely correct.

You have to have the function that describes the curve. Then the 'limits of integration' are the endpoints between which you want to compute the area, and this area is the area UNDER the curve (function).

Once you integrate the function, you use those endpoints and you will then use standard arithmetic to get a numerical answer for the area.

Here is a quick example.

Say I wanted the area under the curve defined by this function:

y = f(x) = x²

And you want the area between say zero and 4 (whatever the units might be).

∫f(x) dx

==> ∫x² dx (limits = 0 to 4)
==> (1/3)x³ (apply the limits....endpoints)
==> (1/3)[4³ - 0³]
==> (1/3)(64)
==> 64/3 (square units)

This is the area of the curve f(x) = x² between zero and 4, and this is how you would approach finding the area of your application.

I almost opted not to go into this detail, but for whatever reason I changed my mind and did it anyway. I hope it wasn't too much, but if so, my apologies and hope it was helpful just the same.

I don't want any points for this. I didn't answer your question any more accurately that the first guy. Give him the points please. I just wanted to add on to what he said.

2006-12-31 02:19:31 · answer #1 · answered by Anonymous · 0 0

If you know the equation of the curve:
y = f(x), then the area bounded by the curve and x-axis from 'x=a' to 'x=b' is:
Integration [ydx lim from 'a' to 'b'] = [f(x)dx lim from 'a' to 'b']

If you want to do it from a graph already plotted:
Draw as many as is possible number horizontal and vertical lines parallel to x-axis and y-axis to form mini-squares.
Count the number of full mini-squares within the curve = m
Then count the number of squares occupying more than half the area of mini-squares = n
Ignore the area occupying less than half the areas of mini-squares.
Your approximate area = m + n
Suppose the dimension of mini-square = 1 mm x 1 mm
Your approximate area = (m + n) sq. mm.
To make it more accurate, make the mini-squares further smaller and count

2006-12-31 10:31:43 · answer #2 · answered by Sheen 4 · 0 0

You need to integrate the function that defines the curve and use the result to compute the area.

2006-12-31 10:07:14 · answer #3 · answered by rscanner 6 · 1 0

I think you do lenght times width i am not sure

2006-12-31 10:07:59 · answer #4 · answered by Merisa Smith 1 · 0 1

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