2006-12-31 01:23:02 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Remove 7 and j since 7 and j appear in BOTH terms.
See it?
We have: 7j
Now divide each term inside the parentheses by the outside term 7j.
7j into 7j^2 = j
7j into 112j = 16
Final answer: 7j(j - 16)
NOTE: If you multiply 7j by (j - 16), you will end up with your ORIGINAL question. This is how to test if factoring was done correctly.
Guido
2006-12-31 01:32:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
7j^2-112j
=7j(j-16)
2006-12-31 09:36:29 · answer #2 · answered by bryant w 1 · 0⤊ 0⤋
7j^2-112j
=7j*j - 7*16j
=7j(j-16)
2006-12-31 09:24:16 · answer #3 · answered by Som™ 6 · 0⤊ 0⤋
7j is common to both terms:
7j(j-16)
2006-12-31 09:43:18 · answer #4 · answered by Renaud 3 · 0⤊ 0⤋
7j² - 112j =
7j (j - 16)
- - - - - -s-
2006-12-31 10:23:54 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
=7j[j-16]
2006-12-31 09:24:45 · answer #6 · answered by openpsychy 6 · 0⤊ 0⤋
7j(j-16)
2006-12-31 09:25:09 · answer #7 · answered by raj 7 · 0⤊ 0⤋