2006-12-31 01:20:14 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
=u^2[u^2-7u-18]
=u^2[u^2-9u+2u-18]
=u^2{u[u-9]+2[u-9]}
=u^2[u+2][u-9]
2006-12-31 01:43:38 · answer #1 · answered by openpsychy 6 · 0⤊ 0⤋
Firstly, u^2(u^2-7u-18)
Then, u^2(u^2-7u-18)= u^2(u-9)(u+2)
If the equation is equivalent to 0, the value of u= 0,9 or -2
2006-12-31 09:25:47 · answer #2 · answered by Juni Mccoy 3 · 0⤊ 0⤋
U⁴- 7u³ - 18u²
u² (u² - 7u - 18)
u² (u² - 9u + 2u - 18)
u² [ u ( u - 9) + 2(u - 9)]
u² (u + 2)(u - 9)
- - - - - - - - - - -s
2006-12-31 10:46:21 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
u^2(u^2-7u-18)
=u^2(u-9)(u+2)
2006-12-31 09:22:10 · answer #4 · answered by raj 7 · 0⤊ 0⤋
u^2=0
u^2-9u+2u-18
u-9
u+2
r the factors
2006-12-31 09:26:23 · answer #5 · answered by well thts it...... 3 · 0⤊ 0⤋