A. 2 and 9
B. 3 and 5
C. 3 and 8
D. 3,8, and,10
2006-12-29 17:55:52 · 4 answers · asked by cuong c 1 in Science & Mathematics ➔ Mathematics
Use 2 simple divisibility tricks:
1. Add the digits of 16,728: 1+6+7+2+8=24, which is divisible by 3 but NOT divisible by 9 => 16,728 is divisible by 3, and NOT divisible by 9 (eliminate A)
2. The last digit is not a 0 or a 5 => NOT divisible by 5, and NOT divisible by 10 (eliminate B and D)
We have eliminated A, B, and D.
So, C must be our answer.
2006-12-29 18:08:43 · answer #1 · answered by alsh 3 · 1⤊ 0⤋
3 and8
2006-12-30 03:59:26 · answer #2 · answered by Nitin T F1 fan 5 · 1⤊ 0⤋
All of them will divide 16,728. A number does not have to be a whole number. Run all of them through a calculator and you'll see.
2006-12-30 02:08:07 · answer #3 · answered by Anonymous · 0⤊ 1⤋
c
2006-12-30 01:58:24 · answer #4 · answered by tom4bucs 7 · 1⤊ 0⤋