The price of a particular car this year is $21,020. This is 7% more than last year's price. What was last year's price, to the nearest cent?
2006-12-29 14:52:04 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
About $19.644.86.
(Divide 21020 by 1.07)
2006-12-29 14:56:00 · answer #1 · answered by Bill P 5 · 0⤊ 0⤋
Price last year=$21,020X100/107
=$19,644.86
2006-12-30 01:17:19 · answer #2 · answered by alpha 7 · 0⤊ 0⤋
Bill P is right.
Let last year's price = x
Last year's price + % increase = This year's price
x + .07x = 21020
1.07x = 21020
x = 19644.86
Therefore, this year's price is $19644.86.
2006-12-30 01:05:05 · answer #3 · answered by TKD Girl 2 · 0⤊ 0⤋
Bill p is correct
$ 21020 = 107 % of original price
107/100 = 1.07
Divide 21020 by 1.07
21020 / 1.07 = 19644.85981
The answer is $ 19644.86
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Check
19644.85981 x 0.07 = 1375.140187
19644.85981 + 1375.140187 = 21020
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2006-12-30 09:24:15 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
take 7 % of 21020 which equals=1471.4 //then last year price=21020-1471.4=19548.6//its right answer cheack it out
2006-12-29 23:13:56 · answer #5 · answered by vish 2 · 0⤊ 0⤋
21,020 .... 100%
x ............... 7%
x = (21,020 x 7) : 100
x = 1,471
Last year's price: 21,020 - 1,471 = $19,550 round
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2006-12-30 00:53:27 · answer #6 · answered by aeiou 7 · 0⤊ 0⤋
It depends on what type of car it is.
2006-12-29 23:35:58 · answer #7 · answered by nich610 2 · 0⤊ 0⤋
21020/1.07
=$19645 approx.
2006-12-29 23:20:18 · answer #8 · answered by raj 7 · 0⤊ 0⤋
$19,549
2006-12-29 23:01:41 · answer #9 · answered by eggshell134 3 · 1⤊ 0⤋