Solve x2 + 7x + 6 = 0 for x?

Question

Solve x2 + 7x + 6 = 0 for x

Answer 1

x² + 7x + 6 = 0

(x + 6) (x + 1)

- - - - - - - - -

Roots

x + 6 = 0

x + 6 - 6 = 0 - 6

x = - 6

- - - - -

x + 1 = 0

x + 1 - 1 = 0 - 1

x = - 1

- - - - - - -

x = - 6

or

x = - 1

- - - - - - - -s-

Answer 2

x² + 7x + 6 = 0
x² + 7x = -6
x² + 7x + (7/2)² = -6 + (7/2)²
(x + 7/2)² = -24/4 + 49/4
(x + 7/2)² = 25/4
x + 7/2 = ± 5/2
x = -7/2 + 5/2 or x = -7/2 - 5/2
x = -2/2 or x = -12/2
x = -1 or x = -6

that's completing the square, which always works, but factoring, when it works, is easier.

x² + 7x + 6 = 0
(x + 6)(x + 1) = 0
x + 6 = 0 or x + 1 = 0
x = -6 or x = -1

Answer 3

x^2 + 7x + 6 = 0
(x + 1)(x + 6) = 0
(x + 1) = 0 or (x + 6) = 0
x = -1 x = -6

Answer 4

just sustitute

0 x 2 + 7 x 0 + 6 = 20

multiply 2 and 7 by 0 then add the products then add 6!

Answer 5

I assume X2 means X^2 and it is a quadratic equation.
factor or use the quadratic formula
I chose to factor as it factors easily w/o doing a lot of algebra
(X+1)(X+6)=0 therefore:

X= -1
and X= -6

Answer 6

x^2 + 7x + 6 = 0
(x + 1)(x + 6) = 0
x = -1 or -6

If you aren't certain of an answer, you can always do this.

x = (-b ± sqrt(b^2 - 4ac))/(2a)

x = (-7 ± sqrt(7^2 - 4(1)(6)))/(2(1))
x = (-7 ± sqrt(49 - 24))/2
x = (-7 ± sqrt(25))/2
x = (-7 ± 5)/2
x = (-12/2) or (-2/2)
x = -6 or -1

Answer 7

x^2 + 7x + 6 = 0
(x+6)(x+1)=0
x+6=0
x=-6
x+1=0
x=-1
x=-6, -1

Answer 8

x ^2+7x+6
=x^2+x+6x+6
=x(x+1)+6(x+1)
=(x+1)(x+6)
i.e,x=-1 or x=-6

Answer 9

(x+1) (x+6) =0
divide first by x +6
x+1 = 0
x = -1
next divide top equation by x +1
then, x+6 =0
x= -6

Answer 10

(x + 6)(x + 1) = 0
x = -6 or x = -1