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What is the slope m and y-intercept point of the line 2x – y = –10?

2006-12-29 14:03:59 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Easiest way to answer this is to solve for y and get it in slope intercept form. that is, get it to look like y = mx + b
Start with 2x - y = -10, and add y and 10 to each side....
2x + 10 = y
So the slope is 2 and the y intercept is (0, 10)

2006-12-29 14:05:55 · answer #1 · answered by Joni DaNerd 6 · 2 0

Slope is calculated as (y2-y1)(x2-x1). to locate the slope of any of those, you will ought to locate 2 factors on the line. the least complicated thank you to do this is in simple terms %. 2 values for x. as an occasion, on the 1st one in each and every of y = 2x-a million %. x = 0 ==> y = 2*0 - a million = -a million %. x = a million ==> y = 2*a million - a million = a million So your 2 factors are (x1,y1) = (0,-a million) and (x2,y2) = (a million,a million) (y2-y1)/(x2-x1) = (a million-(-a million))/(a million-0) = 2/a million = 2 The y intercept is the place the line intersects the y axis. this is an analogous with the aid of fact the fee of the equation whilst X = 0 with the aid of fact the Y axis is a vertical line via X = 0. For the 1st equation, y = 2x - a million If X = 0, y = 2*0 - a million = -a million So the y-intercept is -a million. a lots greater handy way is to look in any respect the equations as y = mx + b the place m is the slope and b is the y-intercept

2016-10-06 04:48:50 · answer #2 · answered by ? 4 · 0 0

First: solve for "y" > subtract 2x from both sides:

2x - 2x - y = - 2x - 10
- y = -2x - 10

Second: "y" can never be negative > change all signs:

y = 2x + 10

Third: the slope is the number/fraction in front of the "x" which is (2). The y-intercept is the number/fraction after the "x" variable which is (10).

2006-12-29 16:54:40 · answer #3 · answered by ♪♥Annie♥♪ 6 · 1 0

y-intercept occurs when x = 0 and so it is found as follows.
2x - y = -10
2x + 10 = y
2(0) + 10 = y
10 = y
y-intercept is at point (0,10)

slope is the chage in y divided by the change in x and so the slope is as follows.

dy/dx = m
((2(0) + 10) - (2(1) + 10)) / (0 - 1) = m
((0 +10) - (2 + 10) ) / (-1) = m
(10 - 12) /(-1) = m
-2 / -1 = m
2 = m

and so the slope is 2.

2006-12-29 14:19:23 · answer #4 · answered by Anonymous · 2 0

You first want to change the equation into the slope-intercept form:
y=mx+b
m=slope
b=y-intercept

Subtract 2x from both sides:
-y=-2x-10

Divide -1 from both sides:
y=2x+10

Slope=2
y-intercept=10

I hope that helped!

2006-12-29 15:25:00 · answer #5 · answered by Anonymous · 3 0

member always change it back to y=mx+c (where m= gradient and c= y-intercept)

swap the 10 and y around and get....

y=2x+10

so..... 10 = y-inetcept and m= 2

2006-12-29 14:10:39 · answer #6 · answered by Anonymous · 2 0

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