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Solve x2 + 7x + 6 = 0 for x

2006-12-29 14:02:37 · 5 answers · asked by shawntaelsey123 1 in Science & Mathematics Mathematics

5 answers

this is factorable..

(x+1)(x+6)=0
and using the zero product rule, which says, A*B=0 if A=0 or B=0..
upon setting x+1 =0
and x+6=0
we get x=-1
and x= -6

2006-12-29 14:06:37 · answer #1 · answered by JAC 3 · 1 0

x^2 + 7x + 6 = 0
(x + 1)(x + 6) = 0
(x + 1) = 0 or (x + 6) = 0
x = -1 x = -6

2006-12-29 22:26:29 · answer #2 · answered by stewartlucas467 2 · 1 0

I presume that you mean x^2 for the first term.

It's a 2nd order polynomial and so has two solutions, not necessarily different.

I'd advise factoring rather than resorting to the lazy person's quadratic formula.

So, can you think of two numbers whose:

product is 6
and
sum is 7
?

(I'll wait.....)

So, those two numbers, r1 and r2, are the roots or solutions of the equation:

x^2+7x+6 = 0
(x-r1)*(x-r2) = 0

Ta da....

2006-12-29 22:08:42 · answer #3 · answered by modulo_function 7 · 1 0

x^2 + 7x + 6 = 0
(x+6)(x+1)=0
x+6=0
x=-6
x+1=0
x=-1
x=-6, -1

2006-12-29 22:19:07 · answer #4 · answered by yupchagee 7 · 1 0

You need to factor the problem:
(x+6)(x+1)=0
x=-6 or -1

2006-12-29 23:18:05 · answer #5 · answered by Anonymous · 0 0

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