2006-12-29 12:51:41 · 6 answers · asked by wicked 1 in Science & Mathematics ➔ Mathematics
Note that sqrt(-144) can be written as sqrt( (-1) * sqrt(144)).
Therefore,
[sqrt (-144)] + 7 = [sqrt (144 *(-1))] + 7
We can decompose a square root of a product to a product of square roots.
[ sqrt(144) sqrt(-1) + 7 ]
Calculating this, we get
[12i + 7]
But in standard form, it must be written as a + bi, so we rewrite it as
7 + 12i
2006-12-29 12:54:18 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
[√(-144)] + 7
= 7 + [√(-144)]
= 7 + [√144] x [√-1]
= 7 + 12 x [√-1]
= 7 + 12i
2006-12-29 12:59:58 · answer #2 · answered by Wendy C 2 · 0⤊ 0⤋
(-+12)+7
2006-12-29 20:30:19 · answer #3 · answered by Nitin T F1 fan 5 · 0⤊ 0⤋
7 + 12i
2006-12-29 12:52:28 · answer #4 · answered by amateur_mathemagician 2 · 0⤊ 0⤋
sqrt(-144) + 7
(12i or -12i) + 7
ANS : 7 + 12i or 7 - 12i or you can just write it as 7 ± 12i
2006-12-29 14:21:03 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
7+2i
2007-01-02 10:23:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋