Math Question?

Question

If x cannot equal 0, than what does (x+1/6x)+(x+1/2x) equal?

Answer 1

Remember that brackets are important. Interpretation of your question can vary. But I'm going to assume that it is:

[x + 1]/[6x] + [x + 1]/[2x]

All we have to do is find the lowest common denominator of these fractions. The answer is 6x. We put both fractions over 6x.

[x + 1]/[6x] + 3[x + 1]/[6x]

Now, we put under a single fraction.

([x + 1] + 3[x + 1]) / [6x]

([x + 1] + 3x + 3) / [6x]
[4x + 4]/ [6x]

The final simplified answer would be

(2/3) [ (x + 1) / x ]

Answer 2

This is the same as adding fractions.

Find the LCD. The LCD is 6x.

Next divide 6x by each denominator and multiply by each numerator.

I will solve one fraction at a time.

Fraction A: x + 1/6x

NOTE: x is really x/1.

6x divided by 1 = 6x and 6x times x = 6x^2

6x divided by 6x = 1 and 1 times 1 = 1.

We get this:

6x^2 + 1...This is our first new fraction.

++++++++++++++++++++++++++++

Do the same to the other fraction: x + 1/2x

NOTE: x is really x/1.

6x divided by 1 = 6x and 6x times x = 6x^2.

6x divided by 2x = 3 and 3 times 1 = 3.

We now have this:

6x^2 + 3...This is our new second fraction.

Next: COMBINE BOTH NEW FRACTIONS and simplify.

6x^2 + 1 + 6x^2 + 3 = (12x^2 + 4)/6x

Next: place into TWO separate fractions and simplify.

(12x^2/6x) + (4/6x)

Final answer: 2x + (2/3)x


Guido

Answer 3

anything
2x +2/3x = y
the range of y -00 to +00 y<>0