2006-12-29 11:46:41 · 10 answers · asked by porcha b 1 in Science & Mathematics ➔ Mathematics
F(n)=11n+1, where n is any positive integer starting at one. F(20)=11(20)+1=221
2006-12-29 11:51:00 · answer #1 · answered by John C 2 · 0⤊ 0⤋
Sequence is 1+11 n
for n= 20,
the result is 1+20*11 = 221
2006-12-29 11:55:53 · answer #2 · answered by imamulleith 2 · 0⤊ 0⤋
the nth term is 1+11n so the 20th term is 1+11*20=221
2006-12-29 13:08:06 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
An = a1 + (n - 1)d
An = 12 + 11(n - 1)
a(20) = 12 + 11(20 - 1)
a(20) = 12 + 11(19)
a(20) = 12 + 209
a(20) = 221
2006-12-29 12:46:58 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
difference is 11. so formula for the nth term is
Fn=11n+c
c is obviously 1 by looking at the value when n=1
F20=11*20+1=221
2006-12-29 12:17:13 · answer #5 · answered by crazy_tentacle 3 · 0⤊ 0⤋
221
2006-12-29 12:10:00 · answer #6 · answered by CAM1122 3 · 0⤊ 0⤋
221
2006-12-29 11:54:39 · answer #7 · answered by anonimous 6 · 0⤊ 0⤋
well, since the terms are separated by 11, and
term 1 = 12
term 2 = term 1 + 11
term 3 = term1 + (3-1)*11
term 20 = term1 + (20-1)*11 = 12 + 19*11
2006-12-29 11:50:22 · answer #8 · answered by firefly 6 · 1⤊ 0⤋
a20 = a1 + (n - 1)*λ
where a1 = 12, n = 20 and λ = 11, so:
a20 = 12 + (20 - 1)*11, a20 = 221
2006-12-29 11:52:06 · answer #9 · answered by Dimos F 4 · 0⤊ 0⤋
d=23-12=11
a=12
t20=a+19d
=12+19*11
=12+209
=221
2006-12-29 11:55:37 · answer #10 · answered by raj 7 · 0⤊ 0⤋