1...All the variables power is 1.
2006-12-29 11:34:32
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answer #1
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answered by feanor 7
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For challenge a million the first step is to combine like words by including and subtracting from both aspect. 5x -2x = 13 -a million Now upload those 3x = 12 now divide by 3 to get x by itself x = 4 As for challenge 2 commence off a similar way 7x - 2x = 8 + 2 combine the words 5x = 10 Now divide by 5 to get x by itself x = 2
2016-12-01 07:48:44
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answer #2
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answered by ? 4
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1- 3x -7y = 2x+8 is linear
it is x-7y -8 =0
2- 2x-8 = y^ 2 is not linear
2006-12-29 12:05:59
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answer #3
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answered by imamulleith 2
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A linear equation is one where all terms are to the first power.
If we solve both of these for y, we see that we still have the form x^1; whereas in the second we have x^(1/2).
So the first equation is the linear equation.
2006-12-29 12:07:36
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answer #4
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answered by Anonymous
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3x-7y=2x+8 is the linear equation
2006-12-29 11:37:05
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answer #5
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answered by Anonymous
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3x - 7y = 2x + 8
-7y = -x + 8
y = (1/7)x - (8/7) or (x - 8)/7
since this is in the form of y = mx + b, this one is linear.
2x - 8 = y^2
y = sqrt(2x - 8)
This problem isn't linear.
2006-12-29 12:49:39
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answer #6
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answered by Sherman81 6
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I assume you mean linear. Equations which result in a graph that is a straight line is called linear. Equations that have exponents equal to 1 and do not have terms like X*Y are linear.
Equation 1 is linear.
Equation 2 is not linear.
2006-12-29 12:08:39
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answer #7
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answered by anonimous 6
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3x-7y=2x+8 is linear
2006-12-29 11:35:21
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answer #8
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answered by raj 7
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The first one, because all the variables appear
to the first power only. In the second one,
the y is squared and that makes it nonlinear.
By the way, "liner" should be spelled "linear".
2006-12-29 11:44:31
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answer #9
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answered by steiner1745 7
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Just the first one, the second one I think would be parabola:
-7y=-x+8
y=1/7x-8/7
2006-12-29 11:45:41
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answer #10
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answered by Anonymous
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1. 2 is not since y^2 term.
2006-12-29 11:34:30
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answer #11
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answered by I know some math 4
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