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27x to the 8th and 3x to the 3rd.

2006-12-29 11:26:11 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

27/3 = 9 and x^8 / x^3 = x^5

x*x*x*x*x*X*X*X
______________ = x*x*x*x*x = x^5
X*X*X


Anabel

2006-12-29 11:28:40 · answer #1 · answered by Anonymous · 0 0

(27x^8)/(3x^3)

27/3 = 9

x^8/x^3 = x^5 [a^m/a^n = a^(m-n)]

ans will be 9x^5.

2006-12-29 11:53:29 · answer #2 · answered by Faraz S 3 · 0 0

27x^8/3x^3=9x^5

2006-12-29 11:33:57 · answer #3 · answered by yupchagee 7 · 0 0

27x^8/3x^3=(27/3)x^(8-3)
=9x^5

2006-12-29 11:34:40 · answer #4 · answered by raj 7 · 0 0

9x^5

2006-12-29 11:28:07 · answer #5 · answered by Anonymous · 0 0

9x^5 is correct if x is nonzero.

2006-12-29 11:43:09 · answer #6 · answered by I know some math 4 · 0 0

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