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which of the following statements best describes what happens as nitrate ions (NO3-) are changed into nitrite (NO2-)

A. The nitrite ions are reduced

B. the nitrite ions are oxidized

C. The nitrate ions are reduced

D. The nitrate ions are oxidized



N2 + 3H2 ------> 2NH3
<-----

A. ammonia is a more stable substance than is N2 or H2

B. As NH3, Forms, some of its reverts back to N2 or H2.

C. All of the reactants are converted to products in the reaction

D. None of these


And as always thank you for all you do!!!!!!

2006-12-29 08:08:45 · 11 answers · asked by cetinnovations 1 in Science & Mathematics Chemistry

11 answers

#1: D-- The nitrate ions lose one electron, turning into nitrite. Thus the nitrate ions are oxidized (Oxidation refers to the loss of electrons, while reduction refers to the gain of electrons)

#2: B, only if the bottom left arrow is right beneath the top right arrow, like this:
---->
<----

2006-12-29 08:34:00 · answer #1 · answered by Mesrour 2 · 0 0

First question:

You need to determine the charge on the N in the NO3-1 and NO2-1. Knowing oxygen is 2- you can figure out:

In NO3-1 the N must be 5+ (3 oxygen = -6 so the N must be 5+ to make the whole thing -1).

In NO2-1 the N must be 3+ (2 oxygen = -4 so the N must be 3+ tomake the whole thing -1),.

So, the N is changing from 5+ to 3+. This represents a gain of electrons so NO3-1 is being reduced (LEO says GER).

2nd question

Since there is a double arrow both the forward and reverse reactions are taking place. That means B is true and C (and D) can not be true. Since you don't know anything else you can not make a judgement about which is more stable so A is out as an answer.

2006-12-30 15:49:34 · answer #2 · answered by The Old Professor 5 · 1 0

C on Question 1.

D on the 2nd question and the reason is the word "or" in answer B. B is correct if the answer says N2 "and" H2. The reaction is reversible, but both N2 and H2 have to be made when NH3 decomposes. In reality there will be an equilibrium established between the two sides with both forming the other to some extent continuously. The extent will depend heavily on Temperature.

2006-12-29 18:11:10 · answer #3 · answered by serf_tide 4 · 0 0

C: The oxidation number of N in NO3- is +5 and in NO2-, +3. Oxidation number is going down, electrons are being gained by NO3-

B: There is a double arrow in the equation, so C cannot be true.

2006-12-29 16:15:49 · answer #4 · answered by steve_geo1 7 · 0 0

AS for the first question I believe inone of then is correct. Nitrogen is the elemnt that is going from an oxidation number of +5 to +3. So the nitrogen is being reduced.

As for the second I also believe is D (None of the above)

2006-12-29 17:38:02 · answer #5 · answered by Yo tu amigo 2 · 0 0

1. c, 2. b

1, the nitrogen atom's charge is being reduced, and in 2. equilibrium dictates that not all the N2 or H2 will be converted, especially in this case, because NH3 really doesn't like to be created.

2006-12-29 17:52:13 · answer #6 · answered by The Frontrunner 5 · 0 0

at the first one the answer is C
because the definition of reduction is losing of oxygen atom so as nitrate contain 3 O LOSE ONE OF THEM to convert into nitrite contain 2 O

the second one the answer is D
Because NH3 is stable compound

2006-12-29 16:24:20 · answer #7 · answered by Storm 2 · 0 1

For your first question, I am pretty sure that the answer is neither B or D (but I am not sure).

I have no clue about your second question--sorry.

Good luck!

2006-12-29 16:14:27 · answer #8 · answered by Nick Name 3 · 0 0

for the first one the answer is (C) .
for the second question the reaction is reverrsible so it's (B)

2006-12-29 18:13:59 · answer #9 · answered by Lord Odesious -II 1 · 0 0

D and C bro

2006-12-29 16:23:14 · answer #10 · answered by brian 2 · 0 0

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