I have Mark Brunell, Rex Grossman, Carson Palmer,
Now I have a question about Palmer playing against Pits?
Would Brunell be a better choice this week?
2006-12-29 06:57:12 · 8 answers · asked by ? 3 in Sports ➔ Fantasy Sports
This one is very simple my friend.
Mark Brunnel does not play anymore. He is out for the season. Scratch....
Rex Grossman will most likely not play the enitre game and he definately wont be playing at 100% because theres not a lot to play for... Scratch
Carson Palmer has everything in the world to play for and if his heads in the game..may have a great day. (Pit is not that good this yr btw)
2006-12-29 07:10:13 · answer #1 · answered by zachary_rubin 2 · 0⤊ 0⤋
Brunell has been benched for the season, just drop him. Grossman sux and I doubt he can perform well with GB's DBs being charles woodson Al Harris. Palmer is the best chance you got, unless Jason cambell is still available on the free agent pool.
2006-12-29 07:20:35 · answer #2 · answered by Garret B 2 · 0⤊ 0⤋
I would go with C.Palmer because Grossman will probably sit out and Brunell shouldn't even be an option.Plus,the Bengals have to win to have any hopes of the playoffs.
2006-12-29 07:06:30 · answer #3 · answered by fsudrew5 2 · 0⤊ 0⤋
Brunell doesn't even play anymore... Grossman will more than likely sit this one out (or most of it) .... You have to go w/Palmer.
2006-12-29 07:02:33 · answer #4 · answered by jh361 5 · 0⤊ 0⤋
Grossman is best but with the bears a clinch he prolly wont play much Palmer is who i would go with. never much cared for brunell myself
2006-12-29 07:40:25 · answer #5 · answered by dragonblood 1 · 0⤊ 0⤋
Play Plamer because the Pits r doing bad
2006-12-29 08:55:55 · answer #6 · answered by Patch G 1 · 0⤊ 0⤋
The Steelers "D" has had several breakdowns in the secondary this year.
Start Palmer
2006-12-29 06:59:31 · answer #7 · answered by Anonymous · 0⤊ 0⤋
rex grossman? eww.. way too inconsistent
gotta go with carlson.. regardless if they are playin' pittsburg
2006-12-29 11:02:16 · answer #8 · answered by do it movin' 1 · 0⤊ 0⤋